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// Exercise 3.2.6 3.2.32 3.2.33 (Solution published at http://algs4.cs.princeton.edu/)
package algs32;
import stdlib.*;
import algs13.Queue;
/* ***********************************************************************
* Compilation: javac BST.java
* Execution: java BST
* Dependencies: StdIn.java StdOut.java
* Data files: http://algs4.cs.princeton.edu/32bst/tinyST.txt
*
* A symbol table implemented with a binary search tree.
*
* % more tinyST.txt
* S E A R C H E X A M P L E
*
* % java BST < tinyST.txt
* A 8
* C 4
* E 12
* H 5
* L 11
* M 9
* P 10
* R 3
* S 0
* X 7
*
*************************************************************************/
public class BST<K extends Comparable<? super K>, V> {
private Node<K,V> root; // root of BST
private static class Node<K extends Comparable<? super K>,V> {
public final K key; // sorted by key
public V val; // associated data
public Node<K,V> left, right; // left and right subtrees
public int N; // number of nodes in subtree
public Node(K key, V val, int N) {
this.key = key;
this.val = val;
this.N = N;
}
}
// is the symbol table empty?
public boolean isEmpty() { return size() == 0; }
// return number of key-value pairs in BST
public int size() { return size(root); }
// return number of key-value pairs in BST rooted at x
private int size(Node<K,V> x) {
if (x == null) return 0;
else return x.N;
}
/* *********************************************************************
* Search BST for given key, and return associated value if found,
* return null if not found
***********************************************************************/
// does there exist a key-value pair with given key?
public boolean contains(K key) {
return get(key) != null;
}
// return value associated with the given key, or null if no such key exists
public V get(K key) { return get(root, key); }
private V get(Node<K,V> x, K key) {
if (x == null) return null;
int cmp = key.compareTo(x.key);
if (cmp < 0) return get(x.left, key);
else if (cmp > 0) return get(x.right, key);
else return x.val;
}
/* *********************************************************************
* Insert key-value pair into BST
* If key already exists, update with new value
***********************************************************************/
public void put(K key, V val) {
if (val == null) { delete(key); return; }
root = put(root, key, val);
//assert check();
}
private Node<K,V> put(Node<K,V> x, K key, V val) {
if (x == null) return new Node<>(key, val, 1);
int cmp = key.compareTo(x.key);
if (cmp < 0)
x.left = put(x.left, key, val);
else if (cmp > 0)
x.right = put(x.right, key, val);
else
x.val = val;
x.N = 1 + size(x.left) + size(x.right);
return x;
}
/* *********************************************************************
* Delete
***********************************************************************/
public void deleteMin() {
if (isEmpty()) throw new Error("Symbol table underflow");
root = deleteMin(root);
//assert check();
}
private Node<K,V> deleteMin(Node<K,V> x) {
if (x.left == null) return x.right;
x.left = deleteMin(x.left);
x.N = size(x.left) + size(x.right) + 1;
return x;
}
public void deleteMax() {
if (isEmpty()) throw new Error("Symbol table underflow");
root = deleteMax(root);
//assert check();
}
private Node<K,V> deleteMax(Node<K,V> x) {
if (x.right == null) return x.left;
x.right = deleteMax(x.right);
x.N = size(x.left) + size(x.right) + 1;
return x;
}
public void delete(K key) {
root = delete(root, key);
//assert check();
}
private Node<K,V> delete(Node<K,V> x, K key) {
if (x == null) return null;
int cmp = key.compareTo(x.key);
if (cmp < 0) x.left = delete(x.left, key);
else if (cmp > 0) x.right = delete(x.right, key);
else {
if (x.right == null) return x.left;
if (x.left == null) return x.right;
Node<K,V> t = x;
x = min(t.right);
x.right = deleteMin(t.right);
x.left = t.left;
}
x.N = size(x.left) + size(x.right) + 1;
return x;
}
/* *********************************************************************
* Min, max, floor, and ceiling
***********************************************************************/
public K min() {
if (isEmpty()) return null;
return min(root).key;
}
private Node<K,V> min(Node<K,V> x) {
if (x.left == null) return x;
else return min(x.left);
}
public K max() {
if (isEmpty()) return null;
return max(root).key;
}
private Node<K,V> max(Node<K,V> x) {
if (x.right == null) return x;
else return max(x.right);
}
public K floor(K key) {
Node<K,V> x = floor(root, key);
if (x == null) return null;
else return x.key;
}
private Node<K,V> floor(Node<K,V> x, K key) {
if (x == null) return null;
int cmp = key.compareTo(x.key);
if (cmp == 0) return x;
if (cmp < 0) return floor(x.left, key);
Node<K,V> t = floor(x.right, key);
if (t != null) return t;
else return x;
}
public K ceiling(K key) {
Node<K,V> x = ceiling(root, key);
if (x == null) return null;
else return x.key;
}
private Node<K,V> ceiling(Node<K,V> x, K key) {
if (x == null) return null;
int cmp = key.compareTo(x.key);
if (cmp == 0) return x;
if (cmp < 0) {
Node<K,V> t = ceiling(x.left, key);
if (t != null) return t;
else return x;
}
return ceiling(x.right, key);
}
/* *********************************************************************
* Rank and selection
***********************************************************************/
public K select(int k) {
if (k < 0 || k >= size()) return null;
Node<K,V> x = select(root, k);
return x.key;
}
// Return key of rank k.
private Node<K,V> select(Node<K,V> x, int k) {
if (x == null) return null;
int t = size(x.left);
if (t > k) return select(x.left, k);
else if (t < k) return select(x.right, k-t-1);
else return x;
}
public int rank(K key) {
return rank(key, root);
}
// Number of keys in the subtree less than x.key.
private int rank(K key, Node<K,V> x) {
if (x == null) return 0;
int cmp = key.compareTo(x.key);
if (cmp < 0) return rank(key, x.left);
else if (cmp > 0) return 1 + size(x.left) + rank(key, x.right);
else return size(x.left);
}
/* *********************************************************************
* Range count and range search.
***********************************************************************/
public Iterable<K> keys() {
Queue<K> q = new Queue<>();
inOrder(root, q);
return q;
}
private void inOrder(Node<K,V> x, Queue<K> q) {
if (x == null) return;
inOrder(x.left, q);
inOrder(x.right, q);
q.enqueue(x.key);
}
public Iterable<K> keys(K lo, K hi) {
Queue<K> queue = new Queue<>();
inOrder(root, queue, lo, hi);
return queue;
}
private void inOrder(Node<K,V> x, Queue<K> queue, K lo, K hi) {
if (x == null) return;
int cmplo = lo.compareTo(x.key);
int cmphi = hi.compareTo(x.key);
if (cmplo < 0) inOrder(x.left, queue, lo, hi);
if (cmplo <= 0 && cmphi >= 0) queue.enqueue(x.key);
if (cmphi > 0) inOrder(x.right, queue, lo, hi);
}
public int size(K lo, K hi) {
if (lo.compareTo(hi) > 0) return 0;
if (contains(hi)) return rank(hi) - rank(lo) + 1;
else return rank(hi) - rank(lo);
}
// height of this BST (one-node tree has height 0)
public int height() { return height(root); }
private int height(Node<K,V> x) {
if (x == null) return -1;
return 1 + Math.max(height(x.left), height(x.right));
}
// level order traversal
public Iterable<K> levelOrder() {
Queue<K> keys = new Queue<>();
Queue<Node<K,V>> queue = new Queue<>();
queue.enqueue(root);
while (!queue.isEmpty()) {
Node<K,V> x = queue.dequeue();
if (x == null) continue;
keys.enqueue(x.key);
queue.enqueue(x.left);
queue.enqueue(x.right);
}
return keys;
}
/* ***********************************************************************
* Check integrity of BST data structure
*************************************************************************/
private boolean check() {
if (!isBST()) StdOut.println("Not in symmetric order");
if (!isSizeConsistent()) StdOut.println("Subtree counts not consistent");
if (!isRankConsistent()) StdOut.println("Ranks not consistent");
return isBST() && isSizeConsistent() && isRankConsistent();
}
// does this binary tree satisfy symmetric order?
// Note: this test also ensures that data structure is a binary tree since order is strict
private boolean isBST() {
return isBST(root, null, null);
}
// is the tree rooted at x a BST with all keys strictly between min and max
// (if min or max is null, treat as empty constraint)
// Credit: Bob Dondero's elegant solution
private boolean isBST(Node<K,V> x, K min, K max) {
if (x == null) return true;
if (min != null && x.key.compareTo(min) <= 0) return false;
if (max != null && x.key.compareTo(max) >= 0) return false;
return isBST(x.left, min, x.key) && isBST(x.right, x.key, max);
}
// are the size fields correct?
private boolean isSizeConsistent() { return isSizeConsistent(root); }
private boolean isSizeConsistent(Node<K,V> x) {
if (x == null) return true;
if (x.N != size(x.left) + size(x.right) + 1) return false;
return isSizeConsistent(x.left) && isSizeConsistent(x.right);
}
// check that ranks are consistent
private boolean isRankConsistent() {
for (int i = 0; i < size(); i++)
if (i != rank(select(i))) return false;
for (K key : keys())
if (key.compareTo(select(rank(key))) != 0) return false;
return true;
}
/* ***************************************************************************
* Visualization
*****************************************************************************/
public String toString() {
StringBuilder sb = new StringBuilder();
for (K key: levelOrder())
sb.append (key + " ");
return sb.toString ();
}
public void toGraphviz(String filename) {
GraphvizBuilder gb = new GraphvizBuilder ();
toGraphviz (gb, null, root);
gb.toFileUndirected (filename, "ordering=\"out\"");
}
private void toGraphviz (GraphvizBuilder gb, Node<K,V> parent, Node<K,V> n) {
if (n == null) { gb.addNullEdge (parent); return; }
gb.addLabeledNode (n, n.key.toString ());
if (parent != null) gb.addEdge (parent, n);
toGraphviz (gb, n, n.left);
toGraphviz (gb, n, n.right);
}
// You may modify "drawTree" if you wish
public void drawTree() {
if (root != null) {
StdDraw.setPenColor (StdDraw.BLACK);
StdDraw.setCanvasSize(1200,700);
drawTree(root, .5, 1, .25, 0);
}
}
private void drawTree (Node<K,V> n, double x, double y, double range, int depth) {
int CUTOFF = 10;
StdDraw.text (x, y, n.key.toString ());
StdDraw.setPenRadius (.007);
if (n.left != null && depth != CUTOFF) {
StdDraw.line (x-range, y-.08, x-.01, y-.01);
drawTree (n.left, x-range, y-.1, range*.5, depth+1);
}
if (n.right != null && depth != CUTOFF) {
StdDraw.line (x+range, y-.08, x+.01, y-.01);
drawTree (n.right, x+range, y-.1, range*.5, depth+1);
}
}
/* ***************************************************************************
* Test client
*****************************************************************************/
public static void main(String[] args) {
//StdIn.fromString ("S E A R C H E X A M P L E");
//StdIn.fromString ("D F B G E A C");
StdIn.fromString ("C A B E D");
BST<String, Integer> st = new BST<>();
for (int i = 0; !StdIn.isEmpty(); i++) {
String key = StdIn.readString();
st.put(key, i);
}
//GraphvizBuilder.nodesToFile (st.root);
st.toGraphviz ("g.png");
// st.drawTree ();
Iterable<String> keys = st.levelOrder();
for (String s : keys)
StdOut.println(s + " " + st.get(s));
// StdOut.println();
// for (String s : st.keys())
// StdOut.println(s + " " + st.get(s));
}
}
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